Model Questions **Paper-2 Class-8 ML Aggarwal** ICSE Mathematics Solutions. APC Understanding Mathematics for ICSE Class-8 Model Question Paper-2 Solutions based on Chapter-5 to 8. Visit official Website **CISCE **for detail information about ICSE Board Class-8 Mathematics.

## Model Question Paper-2 Class-8 ML Aggarwal Solutions

( based on chapter-5 to 8)

Time Allowed-1 hour

max mark-25

**Note**

- Questions 1-2 carry 1 mark each
- Questions 3-5 carry 2 marks each
- Questions 6-8 carry 3 marks each
- Questions 9-10 carry 4 marks each.

**Paper-2 Class-8 ML Aggarwal**

**Choose the correct answer from the given four options (1—2):**

Question 1.

If 295×703 is divisible by 11, then value of x is

(a) 5

(b) 6

(c) 7

(d) 8

#### Answer

∵ 295×703 is divisible by 11

∴ 3 + 7 + 5 + 2 = 17 and 0 + x + 9 = 9 + x

Their difference = 17 – (9 + x) = 8 – x

8 – x = 0

⇒ x = 8 (d)

Question 2.

If C.P. of an article is ₹500 and S.P. is ₹600, then, his profit % is

(a) 10%

(b) 15%

(c) 20%

(d) 25%

#### Answer

C.P. of an article = ₹500

and S.P. = ₹600

Profit = S.P. – C.P. = ₹600 – 500 = ₹100

∴ Profit% = (Profit % = ) = 20% (c)

Question 3.

Find the values of the letters in the following and give reasons for the steps involved:

#### Answer

A + 2 = 9

⇒ A = 9 – 2 = 7

B + 7 = 2 or 12

∴ B = 12 – 7 = 5

∴ A = 7, B = 5

Question 4.

Ramu bought a fan for ₹1080 including 8% VAT. Find the price of fan before VAT was added.

#### Answer

C.P. of a fan including 8% VAT = ₹1080

∴ Price of a fan before VAT

Question 5.

Find the amount and compound interest on ₹2000 for 2 years at 5% per annum, interest payable yearly.

#### Answer

Principal (P) = ₹2000

Rate (R) = 5% p.a.

Time (n) 2 years

∴ Amount (A) =

= ₹2000(

= ₹2200 × = ₹2205

and C.I. = A – P = ₹2205 – ₹2000 = ₹205

Question 6.

If P = {letters of the word HYDERABAD} and Q= {letters ofthewordALLAHABAD}, find

(i) P ∪ Q

(ii) P ∩ Q

Also verify that

n(P ∪ Q) = n(P) + n(Q) – n(P ∩ Q).

#### Answer

P = {letters of the word HYDERABAD} = {H, Y, D, R, E, A, B}

and Q = {letters of the word ALLAHABAD} = {A, L, B, H, D}

(i) P ∪ Q = {H, Y, D, R, L, E, A, R}

(ii) P ∩ Q = {A, H, B, D}

Question 7.

A blanket was marked for ₹500. A shopkeeper allows a discount of 10%. But due to partial damage in the blanket he has to give an extra discount of 20%. Find the S.P. of the blanket.

#### Answer

Marked price (M.P.) of a blanket = ₹500

Discount = 10%

Second discount = 20%

Question 8.

In a 3 digit number unit’s digit, ten’s digit and hundred’s digit are in the ratio 3 : 5 : 7. If the difference of original number and number obtained by reversing the digits is 396, find the number.

#### Answer

In a three digit number,

Ratio in units digit, ten’s digit and hundred’s digit = 3 : 5 : 7

Let unit digit = 3x, then

Tens digit = 5x and

Hundred digit = 7x

Then number = 3x + 5x × 10 + 7x × 100 = 3x + 50x + 700x = 753x

By reversing the order of the digit, the new number will be 357x

∴ 153x – 357x = 396

⇒ 396x = 396

⇒ x = = 1

∴ Number = 753x = 753 × 1 = 753

In an exam atleast 40% marks are required to pass the exam. Rohit uses unfair means to pass the exam but fails by 20 marks. If he scored 220 marks, then find the maximum marks.

Is using unfair means in exam is good? Why should we not use unfair means?

#### Answer

Pass percentage = 40%

Rohit scored = 220 marks blit failed by 20 marks

∴ Pass marks = 220 + 20 = 240

∴ 40% of total marks = 240

∴ Maximum marks = = 600

Using unfair means in an examination is a bad habit and curse on society.

It ruins the life of students. So it should be avoided.

Question 10.

Find the sum invested for years compounded half-yearly at the rate of 8% p.a. that will amount to ₹ 17576.

#### Answer

Amount (A) = ₹17576

Rate (R) = 8% p.a. or 4% half yearly

Period (n) = years or 3 half years

Hence principal = ₹15625

– : End of Model Question** Paper-2 ****Class-8 ML Aggarwal **Solutions :–

Return to **– ML Aggarwal Maths Solutions for ICSE Class -8**

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