**Rational Numbers** Class- 7th RS Aggarwal Exe-4 F Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-4 Rational Numbers for ICSE Class-7 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-4 F to develop skill and confidence. Visit official Website **CISCE** for detail information about ICSE Board Class-7 Mathematics. How do you divide rational numbers? What is the definition of division in rational numbers of class-7th / 6th?

we mentioned that multiplying by a number’s reciprocal is the same as dividing by the number. That’s how we can divide rational numbers; **to divide by a rational number, just multiply by that number’s reciprocal.**

## Rational Numbers Class- 7th RS Aggarwal Exe-4 F Goyal Brothers ICSE Math Solution

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 7th |

Chapter-4 | Rational Numbers |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-4 F |

Academic Session | 2023 – 2024 |

**Exercise – 4 F**

Rational Numbers Class- 7th RS Aggarwal Exe-4 F Goyal Brothers ICSE Math Solution

**1. Find the multiplicative inverse (or reciprocal) of each of the following rational numbers :**

**(i) (6/25)**

**Solution:** (6/25)

= (25/6)

**(ii) -2(3/11)**

**Solution:** -2(3/11)

= (-25/11)

= (-11/25)

**(iii) (-8/9)**

**Solution:** (-8/9)

= (-9/8)

**(iv) (-23/16)**

**Solution:** (-23/16)

= (-16/23)

**(v) 12**

**Solution:** 12

= (1/12)

**(vi) (1/10)**

**Solution:** (1/10)

= 10

**(vii) -6**

**Solution:** -6

= (-1/6)

**(viii) -1**

**Solution:** -1

= (-1/1)

= 1

**(ix) (-1/5)**

**Solution:** (-1/5)

= -5

**(x) (-7/-9)**

**Solution:** (-7/-9)

= (9/7)

**2. Evaluate :**

**(i) (7/12) ÷ (-4/3)**

**Solution:** (7/12) ÷ (-4/3)

= (7/12) × (3/-4)

= (7/-16)

**(ii) (-12/25) ÷ (-5/6)**

**Solution:** (-12/25) ÷ (-5/6)

= (-12/25) × (6/-5)

= (-72/-125)

= (72/125)

**(iii) (-27/32) ÷ (-9/16)**

**Solution:** (-27/32) ÷ (-9/16)

= (-27/32) × (16/-9)

= (-3/-2)

= (3/2)

**(iv) -2(4/7) ÷ (6/35)**

**Solution:** -2(4/7) ÷ (6/35)

= -2(4/7) × (35/6)

= (-18/7) × (35/6)

= -3 × 5

= -15

**(v) 26 ÷ (-1/13)**

**Solution:** 26 ÷ (-1/13)

= (26/1) ÷ (13/-1)

= -338

**(vi) (1/25) ÷ (-5)**

**Solution:** (1/25) ÷ (-5)

= (1/25) × (1/-5)

= (-1/125)

**3. The product of two rational numbers is (2/5). If one of them is (-8/25), find the other.**

**Solution:** Product of two rational no. (2/5)

One no. = (-8/25)

Let the other no. be x.

According to questions –

(-8/25) × x = (2/5)

x = (2/5) × (-25/8)

x = (-5/4)

Other no. is (-5/4).

**4. The product of two rational numbers is (-2/3). If one of them is (16/39), find the other.**

**Solution:** Product of two rational no. (-2/3)

One no. = (16/39)

Let the other no. be x.

According to questions –

(16/39) × x = (-2/3)

x = (-2/3) × (39/16)

x = (-13/8)

Other no. is (-13/8).

**5. By what rational number should (-9/35) be multiplied to get (3/5)?**

[**Hint.** (-9/35) × Other number = (3/5) ⇒ Other number = (3/5) ÷ (-9/35)]

**Solution:** Product of two rational no. (3/5)

One no. = (-9/35)

Let the other no. be x.

According to questions –

(-9/35) × x = (3/5)

x = (3/5) × (-35/9)

x = (-7/3)

Other no. is (-7/3).

**6. By what rational number should (25/8) be multiplied to get (-20/7)?**

**Solution:** Product of two rational no. (-20/7)

One no. = (25/8)

Let the other no. be x.

According to questions –

(25/8) × x = (-20/7)

x = (-20/7) × (8/25)

x = (-32/35)

Other no. is (-32/35).

**7. The cost of 17 pencils is ₹59(1/2). Find the cost of each pencil.**

**Solution:** Cost of 17 pencil = ₹59(1/2) = (119/2)

So, cost of 1 pencil = (119/2) ÷ 17

= (119/2) × (1/17)

= (7/2)

= 3(1/2)

Hance, cost of 1 pencil = ₹3(1/2).

**8. The cost of 20 meters of ribbon is ₹335. Find the cost of each meter of it.**

**Solution:** Cost of 20 meters of ribbon = ₹335

So, cost of 1 meter = ₹335 ÷ 20

= 335 × (1/20)

= (67/4)

Cost of 1 meter ribbon = ₹(67/4)

**9. How many pieces, each of length 2(3/4) m, can be cut from a rope of length 66 m?**

[**Hint.** Number of pieces = 66 ÷ (11/4)]

**Solution:** Total length = 66

Length of each pieces = 2(3/4) = (11/4) m

So, 66 ÷ (11/4)

= 66 × (4/11)

= 24 pieces

**10. Fill in the blanks :**

(i) (….**25**….) ÷ (-5/6) = -30

(ii) (….**6**….) ÷ (-8) = (-3/4)

(iii) (-15/14) ÷ (….**(-3/7)**….) = (5/2)

(iv) (-16) ÷ (….**(-8/3)**….) = 6

**— : end of Rational Numbers Class- 7th RS Aggarwal Exe-4 F Goyal Brothers ICSE Math Solution:–**

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