Friction Obj-2 HC Verma Solutions Vol-1 Ch-6

Friction Obj-2 HC Verma Solutions Vol-1 Chapter-6 Vol-1 Concept of Physics for Class-11. Step by Step Solutions of Objective -2 (MCQ-2) Questions of Chapter-6 Friction  (Concept of Physics) .Visit official Website CISCE for detail information about ISC Board Class-11 Physics.

Friction Obj-2 (MCQ-2) HC Verma Solutions Ch-6 Vol-1 Concept of Physics for Class-11

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Exercise

Friction  Obj-2 (MCQ-2) HC Verma

HC Verma Solutions of Ch-6  Vol-1 Concept of Physics for Class-11

(Page-97)

Question-1 :-

Let F, F_N and f denote the magnitudes of the contact force, normal force and the friction exerted by one surface on the other kept in contact. If none of these is zero.
(a) F > F_N
(b) F > f
(c) F_N > f
(d) F_N − f < F < F_N + f.

Answer-1 :-

The options (a), (b) and (d) are correct

Explanation:

The system is in equilibrium condition when F = f.
Hence, the net horizontal force is zero.
f = μF_N
F > F_N
f = F_N and 0 ≤ μ ≤ 1
Therefore, we can say that F > f. So the net horizontal force is nonzero.
F > f, and so the net horizontal force is zero.
F_N > f ⇒ F_N > μF_{N ⇒} μ < 1
Here, the given relation between F and f i.e
F > f and f = μF_N  will not be satisfied So it cannot be said that the net horizontal force is zero or nonzero.
F_N − f < F < F_N + f
∵ f = μF_N

_{For the above relation, we can say that F ≠ f and so the net horizontal force is nonzero.}

Question-2 :-

The contact force exerted by a body A on another body B is equal to the normal force between the bodies We conclude that
(a) the surface must be frictionless
(b) the force of friction between the bodies is zero
(c) the magnitude of normal force equal that of friction
(d) the bodies may be rough but they don’t slip on each other.

Answer-2 :-

The options  (b) and (d) are correct

Explanation:

The contact force exerted by a body A on another body B is equal to the normal force between the bodies. Therefore, we can conclude that the force of friction between the bodies is zero or the bodies may be rough but they don’t slip on each other.

Question-3 :-

Mark the correct statements about the friction between two bodies.
(a) Static friction is always greater than the kinetic friction.
(b) Coefficient of static friction is always greater than the coefficient of kinetic friction.
(c) Limiting friction is always greater than the kinetic friction.
(d) Limiting friction is never less than static friction.

Answer-3 :-

The options (b) , (c) and (d) are correct

Explanation:

All the above statements are correct. The static friction is sometimes less than the kinetic friction.

Question-4 :-

A block is placed on a rough floor and a horizontal force F is applied on it. The force of friction f by the floor on the block is measured for different values of F and a graph is plotted between them.
(a) The graph is a straight line of slope 45°.
(b) The graph is a straight line parallel to the F-axis.
(c) The graph is a straight line of slope 45° for small F and a straight line parallel to the F-axis for large F.
(d) There is a small kink on the graph.

Answer-4 :-

The options  (c) and (d) are correct

Explanation:

When force F is applied on the block, the force of friction f comes into play. As we increase the  applied F,  the static friction force adjusts itself to become  (equal) to the applied force F  and goes upto  its maximum value equal to limiting friction force.After this ,it is treated as a constant force (i.e . now its value does not change until and unless the body starts moving). If the applied force F is greater than the limiting friction force, then the kinetic friction force comes into play at that time. The kinetic friction force is always less than the limiting friction force.

Question-5 :-

Consider a vehicle going on a horizontal road towards east. Neglect any force by the air. The frictional force on the vehicle by the road
(a) is towards east if the vehicle is accelerating
(b) is zero if the vehicle is moving with a uniform velocity
(c) must be towards east
(d) must be towards west.

Answer-5 :-

When the vehicle is accelerating, the force is applied (by the tyre on the road) in west direction .That causes a net resultant  frictional force acting in east direction. Due to this  force of friction only ,the  car is moving in east direction.
When the vehicle is moving with a uniform velocity, the force of friction on the wheels of the vehicle by the road is zero.

—: End of Friction Obj-2 (MCQ-2) HC Verma Solutions Ch-6 Vol-I :–

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