Integers Class- 7th RS Aggarwal Exe-1B Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-1 Integers for ICSE Class-7 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-1 B to develop skill and confidence. Visit official Website **CISCE** for detail information about ICSE Board Class-7 Mathematics.

## Integers Class- 7th RS Aggarwal Exe-1B Goyal Brothers ICSE Math Solution

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 7th |

Chapter-1 | Integers |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-1 B |

Academic Session | 2023 – 2024 |

**Exercise – 1 B**

Integers Class- 7th RS Aggarwal Exe-1B Goyal Brothers ICSE Math Solution

**Question: 1. Add the following integers :**

**(i) 64 and 36**

**Answer:** Given: 64 and 36

= 64 + 36

= 100

**(ii) 73 and -37**

**Answer:** Given: 73 and -37

= 73 + (-37)

= 73 – 37

= 36

**(iii) -26 and -45**

**Answer:** Given: -26 and -45

= -26 + (-45)

= -26 – 45

= -71

**(iv) -51 and 25**

**Answer:** Given: -51 and 25

= -51 + 25

= -26

**(v) 100 and -32**

**Answer:** Given: 100 and -32

= 100 + (-32)

= 100 – 32

= 68

**(vi) 0 and -21**

**Answer:** Given: 0 and -21

= 0 + (-21)

= 0 – 21

= -21

**Question: 2. Find the additive inverse of :**

**(i) 23**

**Answer:** Additive inverse of 23 is -23

**(ii) -33**

**Answer:** Additive inverse of -33 is 33

**(iii) -1**

**Answer:** Additive inverse of -1 is 1

**(iv) -476**

**Answer:** Additive inverse of -476 is 476

**Question: 3. Evaluate :**

**(i) 6 – 24**

**Answer:** Given: 6 – 24

= 6 – 24

= 18

**(ii) 18 – (-8)**

**Answer:** Given: 18 – (-8)

= 18 + 8

= 26

**(iii) (-16) – (-5)**

**Answer:** Given: (-16) – (-5)

= (-16 + 5)

= -11

**(iv) (-20) – 6**

**Answer:** Given: (-20) – 6

= -20 – 6

= -26

**(v) (-1) – (-19)**

**Answer:** Given: (-1) – (-19)

= -1 + 19

= 18

**(vi) 8 – (-23)**

**Answer:** Given: 8 – (-23)

= 8 + 23

= 31

[**Hint.** a – (-b) = a + b]

**Question: 4. Verify the following :**

**(i) (-14) + 9 = 9 + (-14)**

**Answer:** Given: (-14) + 9 = 9 + (-14)

-14 + 9 = 9 – 14

-5 = -5

∴ L.H.S = R.H.S

**(ii) (-8) + (-12) = (-12) + (-8)**

**Answer:** Given: (-8) + (-12) = (-12) + (-8)

-8 – 12 = -12 – 8

-20 = -20

∴ L.H.S = R.H.S

**(iii) (-6) + [(-8) + 12] = [(-6) + (-8)] + 12**

**Answer:** Given: (-6) + [(-8) + 12] = [(-6) + (-8)] + 12

-6 + [-8 + 12] = [-6 – 8] + 12

-6 + [4] = -14 + 12

-2 = -2

∴ L.H.S = R.H.S

**(iv) [(-9) + (-7)] + (-14) = (-9) + [(-7) + (-14)]**

**Answer:** Given: [(-9) + (-7)] + (-14) = (-9) + [(-7) + (-14)]

[-9 -7] – 14 = -9 + [-7 -14]

[-16] – 14 = -9 + [-21]

-16 – 14 = -9 – 21

-30 = -30

∴ L.H.S = R.H.S

**Question: 5. Fill in the blanks :**

(i) 8 + **(-8)** = 0

(ii) (-10) + **0** = (-10)

(iii) (-6) + (-8) = (-8) + **(-6)**

(iv) (-6) + **(-8)** = -14

(v) (-11) + **4** = (-7)

(vi) (-9) + **8** = -1

**Question: 6. Subtract the sum of -137 and -43 from the sum of -103 and 27.**

**Answer: **Given: (-103 + 27) – [-137 + (-43)]

= -76 – [-180]

= -76 + 180

= 104

**Question: 7. Subtract -29 from -53 and add -16 to the result.**

**Answer:** According to the question: -53 – (-29)

Given: -53 – (-29)

= -53 + 29

= -24

Now, We add (-16) with (-24), we get.

= -24 + (-16)

= -24 – 16

= -40

**Question: 8. The sum of two integers is 43. If one of them is -27, find the other.**

**Answer:** According to the question:

Given is,

one integer = -27

second integer = ?

sum of two integer = 43

Now,

second integer = -27 – (43)

= -70

second integer is -70.

**Question: 9. Find the successor of :**

**(i) 30**

**Answer:** Given: 30

= 30 + 1 [ 1 more than integer]

= 31

**(ii) -70**

**Answer:** Given: -70

= -70 + 1 [ 1 more than integer]

= -69

**(iii) -206**

**Answer:** Given: -206

= -206 + 1 [ 1 more than integer]

= -205

**(iv) -1**

**Answer:** Given: -1

= -1 + 1 [ 1 more than integer]

= 0

**Question: 10. Find the predecessor of :**

**(i) 60**

**Answer:** Given: 60

= 60 – 1 [ 1 less than the integer]

= 59

**(ii) -351**

**Answer:** Given: -351

= -351 – 1 [ 1 less than the integer]

= -352

**(iii) 0**

**Answer:** Given: 0

= 0 – 1 [ 1 less than the integer]

= -1

**(iv) -99**

**Answer:** Given: -99

= -99 – 1 [ 1 less than the integer]

= -100

**— : end of Integers Class- 7th RS Aggarwal Exe-1B Goyal Brothers ICSE Math Solution :–**

**Return to- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions**

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In this question, -137 became 107 It is wrong see:

Question: 6. Subtract the sum of -137 and -43 from the sum of -103 and 27.

Answer: According to the question: (-103 + 27) – [-137 + (-43)]

Given: (-103 + 27) – [-137 + (-43)]

= -76 – [-180]

= -76 + 180

= 104

thanks for getting fault and inform us

again thanks

best of luck for upcoming exam